STRESS TRANSFORMATION

Mohr's Circle Calculator

Transform any plane-stress state (σx, σy, τxy) into principal stresses, maximum shear, and rotated stress components — the fastest way to check yield, fracture, or orientation.

Primary Governing Relation:

σ₁,₂ = (σx+σy)/2 ± √[ ((σx−σy)/2)² + τxy² ]

Mohr Master · 6 calculator modesExact closed-form solutions
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Mohr Master transforms any plane-stress state (σx, σy, τxy) into principal stresses, maximum shear, and rotated stress components with a live interactive circle and step-by-step solutions.

Features Included:
Real-Time Interactive Mohr’s Circle
Principal Stresses σ₁, σ₂ & Max Shear τ_max
3D Stress Tensors & Failure Theories
Step-by-Step Substitution Solutions

Sign Conventions & Geometry

Mohr’s circle turns the algebra of stress transformation into pure geometry. Two conventions must be fixed before drawing: the sign of the stresses and the direction of the rotation angle.

Sign Convention

Normal & Shear Stress

Tensile normal stress is positive; on Mohr’s circle, clockwise shears (positive τxy) plot upward. σ₁ is the algebraically larger principal stress.

Rotation

Angle θ from the x-axis

Counterclockwise physical rotation (CCW θ) is positive. A CCW element rotation moves counterclockwise through 2θ on the circle — the principal planes are found at θp = ½·atan2(2τxy, σx − σy).

Verified Example States

Case a · Standard biaxial tensionMohr Master · verified

σx = 80 MPa · σy = 40 MPa · τxy = 20 MPa

σ₁ / σ₂88.28 / 31.72 MPa
τ_max28.28 MPa
θp22.5°
Case b · Pure shearMohr Master · verified

σx = σy = 0 · τxy = 50 MPa

σ₁ / σ₂50 / −50 MPa
τ_max50 MPa
θp45°
Case c · Uniaxial tensionMohr Master · verified

σx = 100 MPa · σy = 0 · τxy = 0

σ₁ / σ₂100 / 0 MPa
τ_max50 MPa
θp
Case d · Hydrostatic stateMohr Master · verified

σx = σy = 75 MPa · τxy = 0

Radius R0
CircleDegenerates to a point
σ₁ = σ₂75 MPa
Numerical Checks

In case (a): σ_avg = (80 + 40)/2 = 60 MPa, R = √(20² + 20²) = 28.28 MPa, so σ₁ = 88.28, σ₂ = 31.72 MPa, and 2θp = atan2(40, 40) = 45° → θp = 22.5°. In case (b) the circle is centered at the origin with radius 50, so pure shear is equivalent to equal-and-opposite principal stresses. In case (d) the radius vanishes and the circle collapses to a single point — every plane sees σ = 75 MPa and τ = 0.

Engineering Formulas & Governing Equations

Center of Mohr’s Circle (Average Stress)

Equation 01
σ_avg = (σx + σy) / 2

The circle center sits at the mean normal stress on the σ-axis.

Radius of Mohr’s Circle

Equation 02
R = √[ ((σx − σy)/2)² + τxy² ]

The radius measures the maximum shear stress available in the stress state.

Principal Stresses

Equation 03
σ₁, σ₂ = σ_avg ± R

The two in-plane principal stresses occur where the circle crosses the σ-axis (τ = 0).

Principal Plane Angle

Equation 04
tan(2θp) = 2τxy / (σx − σy) ⟹ θp = ½ · atan2(2τxy, σx − σy)

The doubled angle 2θp appears because the circle spans 2θ in stress space. atan2 keeps the correct quadrant.

Maximum In-Plane Shear

Equation 05
τ_max = R, on planes rotated θp ± 45°

The largest shear acts on planes midway between the principal planes, where the normal stress equals σ_avg.

Stress at an Arbitrary Angle θ

Equation 06
σn = σ_avg + ((σx−σy)/2)·cos 2θ + τxy·sin 2θ, τn = −((σx−σy)/2)·sin 2θ + τxy·cos 2θ

Rotating the element by θ in physical space rotates the point by 2θ on the circle.

Invariants of Plane Stress

Equation 07
I₁ = σx + σy = σ₁ + σ₂, I₂ = σx·σy − τxy² = σ₁·σ₂

The sum and product of the two faces’ normal/shear terms are independent of the rotation angle θ.

Frequently Asked Questions

Calculation Details & Clarifications

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